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1.5n^2+39.5n=0
a = 1.5; b = 39.5; c = 0;
Δ = b2-4ac
Δ = 39.52-4·1.5·0
Δ = 1560.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39.5)-\sqrt{1560.25}}{2*1.5}=\frac{-39.5-\sqrt{1560.25}}{3} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39.5)+\sqrt{1560.25}}{2*1.5}=\frac{-39.5+\sqrt{1560.25}}{3} $
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